b^2+4b+5=0

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Solution for b^2+4b+5=0 equation:


Simplifying
b2 + 4b + 5 = 0

Reorder the terms:
5 + 4b + b2 = 0

Solving
5 + 4b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 4b + -5 + b2 = 0 + -5

Reorder the terms:
5 + -5 + 4b + b2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4b + b2 = 0 + -5
4b + b2 = 0 + -5

Combine like terms: 0 + -5 = -5
4b + b2 = -5

The b term is 4b.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4b + 4 + b2 = -5 + 4

Reorder the terms:
4 + 4b + b2 = -5 + 4

Combine like terms: -5 + 4 = -1
4 + 4b + b2 = -1

Factor a perfect square on the left side:
(b + 2)(b + 2) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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